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Euler Tour Subtree Sum using Segment Tree - GeeksforGeeks

    https://www.geeksforgeeks.org/euler-tour-subtree-sum-using-segment-tree/
    Apr 17, 2018 · Euler tour tree (ETT) is a method for representing a rooted tree as a number sequence. When traversing the tree using Depth for search(DFS), insert each node in a vector twice, once while entered it and next after visiting all its children.This method is very useful for solving subtree problems and one such problem is Subtree Sum.. Prerequisite : Segment Tree(Sum of given range)3.3/5

Eulerian path - Wikipedia

    https://en.wikipedia.org/wiki/Euler_tour
    In graph theory, an Eulerian trail (or Eulerian path) is a trail in a finite graph that visits every edge exactly once (allowing for revisiting vertices). Similarly, an Eulerian circuit or Eulerian cycle is an Eulerian trail that starts and ends on the same vertex.They were first discussed by Leonhard Euler while solving the famous Seven Bridges of Königsberg problem in 1736.

THE EULER TOUR TECHNIQUE: EVALUATION OF TREE …

    https://cse.iitkgp.ac.in/~debdeep/courses_iitkgp/PAlgo/Autumn16-17/slides/Lect9EulerCircuit.pdf
    EULER TOUR TECHNIQUE An Euler circuit of a graph is an edge-disjoint circuit which traverses all the nodes. A graph permits an Euler circuit if and only if each vertex has equal indegree and outdegree. An Euler circuit can be used for optimal parallel computation of many tree functions. To construct an Euler circuit, we have to

On Euler tour trees - Codeforces

    https://codeforces.com/blog/entry/18369
    TL;DR: is it possible to construct an Euler tour tree which supports LCA, subtree sum and rerooting?. Euler tour tree (ETT) is a method for representing a rooted undirected tree as a number sequence. There are several common ways to build this representation.

eseq: Construct eulerian paths on the complete graph where ...

    https://rdrr.io/cran/PairViz/man/eseq.html
    In PairViz: Visualization using Graph Traversal. Description Usage Arguments Details Value Author(s) References See Also Examples. View source: R/eseq.R. Description. Constructs an eulerian on the complete graph where nodes are integers 1..n. The result in an euler tour for odd n.For even n the result is not exactly an euler tour or path because (n-2)/2 edges must be visited twice.

Euler and Hamiltonian Paths and Circuits Mathematics for ...

    https://courses.lumenlearning.com/wmopen-mathforliberalarts/chapter/introduction-euler-paths/
    Determine whether a graph has an Euler path and/ or circuit; ... Your teacher’s band, Derivative Work, is doing a bar tour in Oregon. The driving distances are shown below. Plan an efficient route for your teacher to visit all the cities and return to the starting location. Use NNA starting at …

Fleury's Algorithm for printing Eulerian Path or Circuit ...

    https://www.geeksforgeeks.org/fleurys-algorithm-for-printing-eulerian-path/
    Nov 25, 2019 · Euler tour becomes ‘2-0 0-1’. There is only one edge from vertex ‘1’, so we pick it, remove it and move to vertex ‘2’. Euler tour becomes ‘2-0 0-1 1-2’ Again there is only one edge from vertex 2, so we pick it, remove it and move to vertex 3. Euler tour becomes ‘2-0 0-1 1-2 2-3’

Euler Paths and Circuits - Discrete Mathematics

    http://discrete.openmathbooks.org/dmoi/sec_paths.html
    Section 4.5 Euler Paths and Circuits ¶ Investigate! An Euler path, in a graph or multigraph, is a walk through the graph which uses every edge exactly once. An Euler circuit is an Euler path which starts and stops at the same vertex. Our goal is to find a quick way to check whether a graph (or multigraph) has an Euler path or circuit.

Chinese Postman Problem

    https://personal.utdallas.edu/~dzdu/cs6363/Chinese.htm
    Now it's time to construct an Euler tour from A. The algorithm will consider the double paths between the vertices in path m and produce a tour that can start and end at A. The tour will just cover the edges in m twice instead of once. Let's calculate the total weight of the tour. To begin with, the total weight of all the edges of graph P was 62.

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